Sorry if you've already done this but it's not clear from your message.

Is C:\Tomcat\jakarta-tomcat-4.1.12\bin\startup.bat exactly what you've
entered? Ie: at the command prompt.

That is

C:
Cd tomcat\jakarta-tomcat-4.1.12\bin
Startup.bat

If the above is returning a "can't find this thing" type message then
the first thing to check is that it's actually there (typos in the path
etc).  

Alternatively:
Have you got your JDK in your path?
Ie: PATH=C:\path\to\your\jdk\bin


cheers

------------------------------------------------------
Tref Gare
Development Consultant
Areeba
Level 19/114 William St, Melbourne VIC 3000
email: [EMAIL PROTECTED]
phone: +61 3 9642 5553
fax: +61 3 9642 1335
website: http://www.areeba.com.au
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-----Original Message-----
From: Siobhan Quigley [mailto:[EMAIL PROTECTED]] 
Sent: Tuesday, 10 December 2002 7:45 AM
To: [EMAIL PROTECTED]
Subject: Problems with starting Tomcat 4.1.12 - PLEASE HELP

I have installed the Java SDK and Tomcat 4.1.12 (release version).  I
have set the JAVA_HOME  and the
CATALINA_HOME  variables and did the ECHO test.  When I try to start up
Tomcat, I type
C:\Tomcat\jakarta-tomcat-4.1.12\bin\startup.bat but I get an error
message saying it can not
find the path specified.

What do I need to type to (a) start the application and (b) shut down
the
application.? (I am a complete beginner)

Thanks for your help

rocket



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