>>> Starting an .exe though out of a servlet

[Patrick Kosiol]

Hi,

I'm runnung TomCat 4.0.4 and I want to start an external .exe-File.
My Code:

String[] runString = {relativeDataPath + "data.exe",
parameter0, parameter1, parameter2, parameter3};
Process p = Runtime.getRuntime().exec(runString);
System.out.println(runString);
if(p.waitFor() == 0){
........

The 'data.exe'-File is placed in $CATALINA_HOME/webapps/ROOT/relativeDataPath so it should be no problem to access this File. The Number of Parameters etc. is OK.
But I get the following Error-Message:

java.io.IOException: CreateProcess: 'relativeDataPath'/bfpldata.exe parameter0 parameter1 parameter2 parameter3 error=3

Does someone know what 'error=3' mean? And how can I access this 'data.exe' and execute this File with the Parameters? The starting-routine seems to be correct.


Thx
Patrick


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