Hi,
I'm runnung TomCat 4.0.4 and I want to start an external .exe-File.
My Code:
String[] runString = {relativeDataPath + "data.exe",
parameter0, parameter1, parameter2, parameter3};
Process p = Runtime.getRuntime().exec(runString);
System.out.println(runString);
if(p.waitFor() == 0){
........
The 'data.exe'-File is placed in
$CATALINA_HOME/webapps/ROOT/relativeDataPath so it should be no problem
to access this File. The Number of Parameters etc. is OK.
But I get the following Error-Message:
java.io.IOException: CreateProcess: 'relativeDataPath'/bfpldata.exe
parameter0 parameter1 parameter2 parameter3 error=2
error=2 means imho that the File is not found. How can I execute my file
to do that, what I want. Is it possible that the process can create
files in the Tomcat folders?
Thx
Patrick
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