Derrick,
The following demonstrates how to create an XML file from an existing model
that didn't start off as an XML file:
1. Create a new model
2. import /TopBraid/Examples/kennedys.rdf and /TopBraid/TBC/sxml.rdf into it
3. run the query below
4. assert the triples it creates
5. do a Save As to a file with an extension of .xml
You will see an XML file following this pattern:
<kennedies>
<kennedy birthYear="1923">Peter Lawford</kennedy>
<kennedy birthYear="1967">Alfred Tucker</kennedy>
<kennedy birthYear="1928">Jean Kennedy</kennedy>
<!-- etc. -->
</kennedies>
The query:
CONSTRUCT {
:kennedys a owl:Class;
rdfs:subClassOf owl:Thing ;
sxml:element "kennedies" ;
rdfs:label "kennedies" .
:kennedy-birthYear a owl:DatatypeProperty ;
sxml:attribute "birthYear" ;
rdfs:label "color" ;
rdfs:domain :kennedy .
:Document a sxml:Document ;
sxml:root :kennedysInstance .
:kennedysInstance a :kennedys ;
composite:child ?k .
:kennedy a owl:Class;
rdfs:subClassOf owl:Thing ;
sxml:element "kennedy" ;
rdfs:label "kennedy" .
?k rdf:type :kennedy ;
:kennedy-birthYear ?birthYear ;
composite:child _:textNode .
_:textNode rdf:type sxml:TextNode ;
sxml:text ?fullName .
}
WHERE {
?k a kennedys:Person ;
kennedys:birthYear ?birthYear ;
kennedys:firstName ?firstName ;
kennedys:lastName ?lastName .
BIND (concat(?firstName," ",?lastName) as ?fullName ).
}
If I was going to do this with additional Kennedys data as on a regular
basis, I would split up the query above into different SPIN rules for the
appropriate classes, but your data will have different classes, so where you
put the SPIN rules depends on what classes you're working with. (I also
would define a prefix for my new file and use it in the SPARQL query instead
of the default prefix of :, but this was just a quick example for demo
purposes.) All the logic is demonstrated in the query above, though: which
classes and properties need to be declared, how to get data into the XML
elements and attributes, and what has to point at what.
To put the result XML's kennedy elements in a specific order in the XML, I
would have set the composite:index property for each ?k instance to 1, 2, 3,
etc.
If you create an XML document that looks like the target you'd like to
export to and then import it as semantic XML, you'll see the kinds of
classes and properties that TopBraid uses to represent that XML document as
triples, and can use logic like that shown above to create them.
See also the TopBraid Composer help: TopBraid Composer > Import and Export >
Handling XML documents with Semantic XML (ME).
Bob
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of
[email protected]
Sent: Thursday, September 15, 2011 10:49 AM
To: TopBraid Suite Users
Subject: [topbraid-users] Re: RDF/OWL conversion to XML instancies
Bob:
Could you provide or point me to an example of the type of SPIN rules
to do this?
Derrick
On Sep 15, 9:08 am, "Bob Ducharme" <[email protected]> wrote:
> Right now there is no automated export of instances conforming to a
> particular OWL model to XML.
>
> TopBraid's Semantic XML (SXML) ontology makes it possible to import XML as
> triples and then round-trip it back to XML, and would make it possible to
> create new XML documents from existing triples. If you create an XML
> document following the model you'd like to see exported and then, in
> TopBraid Composer, right-click it in the Navigator and pick Open With
> TopBraid (Semantic XML Documents), it will open it as RDF with the sxml
> ontology imported. Editing and saving it will save it as XML.
>
> To save the instances described below as XML, you could use SPARQL (in
SPIN
> rules attached to each class to transform, if you wanted to automate this)
> to create semantic XML triples following the example of the imported
> document described above from your existing triples and then save that.
>
> Bob DuCharme
>
>
>
> -----Original Message-----
> From: [email protected]
>
> [mailto:[email protected]] On Behalf Of
> [email protected]
> Sent: Wednesday, September 14, 2011 12:40 PM
> To: TopBraid Suite Users
> Subject: [topbraid-users] RDF/OWL conversion to XML instancies
>
> I have created a very simple OWL Class that subclasses owl:Thing. It
> contains one object reference and 5 data type properties. I will
> eventually have several dozen instances of this class that must be to
> converted to XML for use by software programs. The XML
> conversion(Manual process using TBM to date) produced a reasonable XSD
> but no instances. What must I do to get them? In addition, the object
> property in the schema I would like to be converted to its URI in the
> resulting xml. Is this doable? Currently using version 3.4.0. Any
> insight would be helpful.
>
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