You can do it in bash using something similar to the following:
#!/bin/bash
# $@ represents all the arguments except the name of the program '$0'
#
# this executes the command in the background and kills it after 10
# minutes if it is still running.
#
$@ >/dev/null 2>&1 &
pid=$!
sleep 600
if kill -0 $pid >/dev/null 2>&1 ; then
# still alive, but not for long
kill -HUP $pid
sleep 2
if kill -0 $pid >/dev/null 2>&1 ; then
kill -TERM $pid
sleep 2
if kill -0 $pid >/dev/null 2>&1 ; then
kill -KILL $pid # murder it!
fi
fi
fi
# end of script.
I don't promise the above script is error free, but you get the idea.
'$!' represents the pid of the last background process. You might want
to 'disown' the process after you have the pid too.
-Weave
Wesley Zhang [EMAIL PROTECTED] wrote on Fri, Jan 21, 2005 at 11:49:15AM -0500:
> Hi All,
>
> I am a newbie on shell script. But I would like to use linux shell
> script to control a job that runs forever and will be terminated after
> 10 minute. My thought for this is following:
>
> pid = start-job-for ("cmd") // has to be a separate process
> sleep 10 min
> kill pid.
>
> How can I spawn a separate process to execute my command and get the
> proper process id?
>
> Thanks,
> Wesley
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