#920: change identity prompt in quickstart
----------------------+-----------------------------------------------------
Reporter: fredlin | Owner: anonymous
Type: defect | Status: new
Priority: low | Milestone: 0.9
Component: Identity | Version: 0.9a6
Severity: trivial | Keywords: quickstart
----------------------+-----------------------------------------------------
origin identity prompt in quickstart is:
{{{
Do you need Identity (usernames/passwords) in this project? [no]:
}}}
The identity prompt in quickstart notice me to type 'yes' to trigger
identity functions,
and it's annoying to type 'yes', 'no' to trigger Identity template(I've to
use two hands to type that:P ).
I just found to accept abbrev type (y/n) is possible in the code
(quickstart.py),
So why not change '[no]' to unix type 'yes/no[default value]' for better
guidance(cause its a 'quickstart')
The prompt is:
{{{
Do you need Identity (usernames/passwords) in this project? yes/no[n]
}}}
----
and for consist, I suggest to change following prompt from
{{{
Select your provider sqlobject or sqlalchemy [sqlobject]:
}}}
to
{{{
Select your provider: sqlobject/sqlalchemy[sqlobject]:
}}}
and make 'so' or 'sa' can be recognize as 'sqlobject' or 'sqlalchemy'
code is here(in quickstart.py)
{{{
#!diff
Index: quickstart.py
===================================================================
--- quickstart.py (revision 1516)
+++ quickstart.py (working copy)
@@ -131,7 +131,7 @@
doidentity = None
while not doidentity:
doidentity = raw_input("Do you need Identity "
- "(usernames/passwords) in this project? [no] ")
+ "(usernames/passwords) in this project?
yes/no[n]: ")
doidentity = doidentity.lower()
if not doidentity or doidentity.startswith('n'):
self.identity="none"
@@ -142,10 +142,14 @@
doidentity = None
while not self.identity:
- self.identity = raw_input("Select your provider sqlobject or
sqlalchemy [sqlobject]: ")
+ self.identity = raw_input("Select your provider:
sqlobject/sqlalchemy [sqlobject]: ")
+ if (self.identity=='so'):
+ self.identity== "sqlobject"
+ if (self.identity=='sa'):
+ self.identity== "sqlalchemy"
if not self.identity:
self.identity = "sqlobject"
- if self.identity not in ["sqlobject", "sqlalchemy"]:
+ if self.identity not in ["sqlobject", "sqlalchemy", 'so',
'sa']:
print "Please enter one of 'sqlobject(so)',
'sqlalchemy(sa)'"
self.identity = ""
continue
}}}
--
Ticket URL: <http://trac.turbogears.org/turbogears/ticket/920>
TurboGears <http://www.turbogears.org/>
TurboGears front-to-back web development
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