Finding the all the roots of a complex number shouldn't be too difficult. I tend to do it on paper sometimes. Maybe I can write a script to do it for me instead. I stongly caution you though. The methods that I show below are unstable and should be verified by a math web site as it has been quite a few months since I last used the equations. In fact, I'll almost bet they're wrong. If you want me to check them, I'll gladly google for the right equations if you want.
where i == sqrt(-1) [pseudo-code] p = (a+bi)**n n = polar(p) ## polar is a function that converts rectangular coordinates to polar coordinates. radius = n[0] angle = n[1] 1st root radius**n cis (angle/(180*n)) ## Where cis is short for (cos(angle) + i*sin(angle)) 2nd root radius**n cis (angle/(360*n)) ... qth root radius**n cis (angle/(180*q*n)) [/pseudo-code] So saying, I would set a for i in range loop for n times to run these root finders through. Note unless you call some sort of polar to rectangular function on the roots, they will still be in polar. HTH as always, Jacob Schmidt _______________________________________________ Tutor maillist - [EMAIL PROTECTED] http://mail.python.org/mailman/listinfo/tutor
