Thanks all, that was very helpful!
On Tuesday, December 14, 2004, at 06:39 PM, Brian van den Broek wrote:
Marc Gartler said unto the world upon 2004-12-14 18:12:
Hi all,
I am fairly new to both Python & programming, and am attempting to
create a function that will test whether some user input is an
integer between 10 and 89, but the check isn't happening...
def check_range(myrange):
if range(myrange) != range(10,89):
return "False"
else:
return "True"
...this gets called later via:
if check_range(input):
done = "True"
return int(input)
What am I doing wrong?
Thanks!
Hi Marc,
Welcome to Python and the list. :-)
Others have pointed out how to solve your immediate problem with in or
a comparison, and that you can just return True and False unquoted.
(They are special builtin objects, so making strings for them isn't
needed.)
A minor correction to Kent's suggestion, though. He suggested to use
10 < x < 90, but since I gather you want 10 to return True, you need
9 < x < 90:
>>> 10 < 10 < 90
False
>>> 9 < 10 < 90
True
This sort of thing is an "off by 1 error" and will happen to you all
the time :-(
I have a some style suggestions for you, too.
Try it this way:
>>> def check_in_range(value):
in_range = False
if 9 < value < 90:
in_range = True
return in_range
>>> check_in_range(35)
True
This way, by setting a name to point to False, and over-riding that
when the test is met, there is only a single return statement. That is
often considered a good thing. This function is too small for it to
matter lots, but have multiple returns can make the debugging a bit
harder.
Another tip is that for debugging such things it often helps to use
print statements when things don't go as expected. If you'd added them
to your original function like so:
>>> def check_range(myrange):
print range(myrange)
print range(2,5)
if range(myrange) != range(2,5):
return "False"
else:
return "True"
>>> check_range(3)
[0, 1, 2]
[2, 3, 4]
'False'
The problem would have likely been much more clear.
HTH,
Brian vdB
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http://mail.python.org/mailman/listinfo/tutor
