Hi all,
I'm writing some code, and I want to take a given path + filename, and change the file extension to *.bak.
In doing so, (entirely internal this function), I am assuming -
That the file will always have an extension Thathe extension will vary But, it will follow the general DOS format of name.ext
So, I came up with this -
a="./tc/arc/gab.pct"
x=a.replace(a[a.rfind('.'):len(a)],'.bak')
x="./tc/arc/gab.bak"
So, it works, but it feels a bit, well, hacky to me. Not nearly hacky as using an regex though ; )
I thought about
a="./tc/arc/gab.pct"
aList=a.split('.') aList[-1]='bak' a=".".join(aList)
but I'm wondering if there's a simpler way, as there usually seems to be, and it's always so obvious once I'm shown it, like 6 down - Six on vehicle live in the manse (VI + car). Obvious once you know.
Regards,
Liam Clarke
Hey Liam!
The os.path module is your friend, especially split and splitext: http://docs.python.org/lib/module-os.path.html
HTH, Wolfram
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