Although, (and this will be rough) a list comprehension would be probably do the same thing j=[1, 2,3,4, 5,6,7,8]
q = [if not item % 2 for item in j]
I really think I've got that 'if not item % 2' wrong, as I can't test it, but I'd be hoping for print q [1, 3, 5, 7]
Backwards. ;-)
q = [item for item in j if not item % 2 == 0]
A word of warning. You want odd numbers, so even if the syntax was correct for your list comprehension, you would have gotten even numbers -- item % 2 would register False if item %2 == 0, then not False would be True so you would get all of the items that were even. Does that make sense?
You could also do
q = [item for item in j if item % 2]
Which says if item % 2 is True (not equal to False, 0) then append item to q. Okay, so that's not exactly what it says
HTH,
Jacob
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