Thanks to everyone who replied to my post. All of your suggestions seem to work. My thanks
Ron --- Ryan Davis <[EMAIL PROTECTED]> wrote: > You could use split() to split the contents of the > file into a list of strings. > > ### > >>> x = 'asdf foo bar foo' > >>> x.split() > ['asdf', 'foo', 'bar', 'foo'] > ### > > Here's one way to iterate over that to get the > counts. I'm sure there are dozens. > ### > >>> x = 'asdf foo bar foo' > >>> counts = {} > >>> for word in x.split(): > ... counts[word] = x.count(word) > ... > >>> counts > {'foo': 2, 'bar': 1, 'asdf': 1} > ### > The dictionary takes care of duplicates. If you are > using a really big file, it might pay to eliminate > duplicates from the list > before running x.count(word) > > Thanks, > Ryan > > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of Ron > Nixon > Sent: Tuesday, February 15, 2005 11:22 AM > To: tutor@python.org > Subject: [Tutor] count words > > > I know that you can do this to get a count of home > many times a word appears in a file > > > f = open('text.txt').read() > print f.count('word') > > Other than using a several print statments to look > for > seperate words like this, is there a way to do it so > that I get a individual count of each word: > > word1 xxx > word2 xxx > words xxx > > etc. > > > > > > __________________________________ > Do you Yahoo!? > Yahoo! Mail - Find what you need with new enhanced > search. > http://info.mail.yahoo.com/mail_250 > _______________________________________________ > Tutor maillist - Tutor@python.org > http://mail.python.org/mailman/listinfo/tutor > > _______________________________________________ > Tutor maillist - Tutor@python.org > http://mail.python.org/mailman/listinfo/tutor > __________________________________ Do you Yahoo!? The all-new My Yahoo! - Get yours free! http://my.yahoo.com _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor