Hi, I've slightly modified the for-Loop containing the "else" and not the if:
>>> x = [[1,2,3],[2,4,6],[8,4,5,6],[9,8,7]] >>> for num in x: ... if 5 in num: ... break ... else: ... print "YES" ... >>> second test: >>> x = [[1,2,3],[2,4,6],[8,4,6],[9,8,7]] >>> for num in x: ... if 5 in num: ... break ... else: ... print "YES" ... YES >>> The else-Part is only executed, when the for ( or while) - loop is left regularly, without a break-statement. HTH Ewald on Tue, 19 Apr 2005 11:51:39 +0800 Ching-Yi Chan <[EMAIL PROTECTED]> wrote : --------------------------------------------------------------------------------------------- Ching-Yi Chan > *Ron A* /Wed Jan 7 18:41:15 EST 2004/ Ching-Yi Chan > Ching-Yi Chan > I'm experimenting and would like 'yes' to be printed only if 5 is not in Ching-Yi Chan > the list, but I want to look in each list. This prints out two yeses. Ching-Yi Chan > How do I get it to print just one 'yes'? Ching-Yi Chan > Ching-Yi Chan > x = [[1,2,3],[2,4,6],[8,4,5,6],[9,8,7]] Ching-Yi Chan > Ching-Yi Chan > for num in x: Ching-Yi Chan > if 5 in num: Ching-Yi Chan > break Ching-Yi Chan > else: Ching-Yi Chan > print 'yes' Ching-Yi Chan > Ching-Yi Chan > -------------------------------------------------------------------------- Ching-Yi Chan > Ching-Yi Chan > Hi, I read the code and consider for a while, you can try it : Ching-Yi Chan > Ching-Yi Chan > x = [[1,2,3],[2,4,6],[8,4,5,6],[9,8,7]] Ching-Yi Chan > print [ e for e in x if 5 in e] Ching-Yi Chan > Ching-Yi Chan > Ching-Yi Chan > _______________________________________________ Ching-Yi Chan > Tutor maillist - Tutor@python.org Ching-Yi Chan > http://mail.python.org/mailman/listinfo/tutor Ching-Yi Chan > ------------------- end ---------------------- _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor