> Is there a more pythonic way of doing this other than, > > if (a == b & > a == c & > a == d & > a == e & > a == f & > a == g): > do stuff
You don't want to use & coz its a bitwise comparison, so you should use 'and'.... if a == b and a == c and ... However you can also do the more intuitive: if a == b == c == d == e == f == g: do stuff Anther slightly mor flexible but much more obscure way uses comprehensions: if [item for item in [a,b,c,d,e,f,g] if item != a]: which returms an empty list(false0 if they are all equal. The comprehensions advantage is that you can keep the list separate from the check and add, remove items and it doesn't break working code, each hard coded test would need to be modified in the event of a change. Finally old assembler hackers will no doubt want to use xor: if not (a^b^c^d^e^f): do it :-) PS. The last works for primitive types but is not intended to be a serious suggestion!! HTH, Alan G Author of the Learn to Program web tutor http://www.freenetpages.co.uk/hp/alan.gauld _______________________________________________ Tutor maillist - [email protected] http://mail.python.org/mailman/listinfo/tutor
