> #this function returns the number of lines on record for each log file. > def line_finder(LogsInDir, flag): > flag=flag.strip() > return_next=False > for line in LogsInDir: > if return_next: > return line.strip() > else: > if line.strip() == flag: > return_next = True
Hi Nephish, Question: what should the program return if return_next is never True? That is, what happens if the program does not find the flag that you're looking for? The comment of this function also seems a bit weird: it appears to try to return the very next line after the 'flag' line of a file: it's not doing any counting of numbers, as far as I can tell. > the line in question is this one: > > NumLinesOnFile=line_finder(LogsRead, LogsInDir[NextLog]) > print NumLinesOnFile > > if i run this in idle printing NumLinesOnFile gives me a string 14 The function will return None if 'flag' can't be found in the LogsRead list. Otherwise, it'll return one of the lines of the file. So I'd assume for the moment that line_finder can't find what it is trying to find. You may want to test this yourself by adding some kind of debugging statement in line_finder() to make it more clear if t can't find what it's looking for. Does this sound reasonable? Best of wishes to you! _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
