> coin = random.randrange(2) That's the problem there...you've got coin assigned outside the while loop, so it is assigned 0 or 1 once, before the loop, and then you're running 100 checks on the same value.
If you move > coin = random.randrange(2) to inside the while loop before the if statement, you'll get the result you want. -Jay On Monday 08 August 2005 5:41 pm, Will Harris wrote: > I am working my way through "python programming for the absolute beginner" > and one of the challenges is to create a program that will flip a coin 100 > times and tell you how many of each it did. Now I have it flipping the > coin, but when I try to do this 100 times I end up with it running through > 100 times, but always the same result comes back. It will either be 100 > heads, or 100 tails. I have tried if statements and while loops and both > seem to give me all or nothing. I am just looking for a hint at the > direction to look of adjust to get the code below working not really the > solution. Thanks in advanced for any tips. > > #!/usr/bin/python > import random > > coin = random.randrange(2) > > count = 0 > head_count = 0 > tail_count = 0 > > while (count != 100): > if coin == 0: > print "You got Heads!" > head_count = head_count + 1 > count = count + 1 > else: > print "You got Tails!" > tail_count = tail_count + 1 > count = count + 1 > > print "Out of", count, "you flipped", head_count, "heads and ", tail_count, > "tails" > > _______________________________________________ > Tutor maillist - Tutor@python.org > http://mail.python.org/mailman/listinfo/tutor _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor