Kent Johnson wrote:
Scott Oertel wrote:
The next problem I have though is creating the dict,
i have a loop, but i can't figure out how to compile the dict, it is
returning this: ('Joey Gale', ('Scott Joe', 'This is lame' )))
listofnames = []
while (cnt < number[1][0]):
if (date[2] == today[2]):
test = regex.findall(M.fetch(int(number[1][0]) - cnt,
'(BODY[HEADER.FIELDS (FROM)])')[1][0][1].rstrip())
cnt += 1
if (nameofsender != []):
print nameofsender[0]
listofnames = nameofsender[0], listofnames
I think you want
listofnames.append(nameofsender[0])
which will add nameofsender[0] to the list. What you have -
listofnames = nameofsender[0], listofnames
is making a tuple (a pair) out of the new name and the old list, and assigning it to listofnames. Kind of like CONS in LISP - but Python lists are more like arrays than like LISP lists.
Kent
else:
no_name += 1
else: break
------------------------------------------------------------------------
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_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
Thank you everyone, this is exactly it, I'm going to take that link
from byron and read up on dicts/lists.
-Scott Oertel
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