Hi Kent,
Once again, thanks a lot. Problem solved now, your suggestions work
like a charm. You were absolutely right about the last group matching.
I modified my matching pattern:
oRe = re.compile( "(\d\d_\d\d\_)(\d\d(\D|$))" )
Instead of
oRe = re.compile( "(\d\d_\d\d\_)(\d\d)" )
I had no idea you could put subgroups in groups, I tried that out of
inspiration and whoo it works. This is fantastic!
So here is the full script, followed by the output:
import os, re
def matchShot( sSubString, oRe ):
sNewString = oRe.sub( r'\g<1>0\2', sSubString )
return sNewString
def processPath( sString, bTest ):
"""
ARGUMENTS:
sString (string): the path to process
bTest (boolean): test the validity of paths at each step of the script
"""
# Create regular expression object
oRe = re.compile( "(\d\d_\d\d\_)(\d\d(\D|$))" )
if bTest == True:
# Test validity of integral path
if not os.path.exists( sString ): return None
# Break-up path
aString = sString.split( os.sep )
aNewPath = []
# Iterate individual components
for sSubString in aString:
if bTest == True:
# Test if this part of the path is working with the
current path
sTempPath = '\\'.join( aNewPath )
sTempPath += '%s%s' % ( '\\', sSubString )
if not os.path.exists( sTempPath ): sSubString =
matchShot( sSubString, oRe )
else: sSubString = matchShot( sSubString, oRe )
aNewPath.append( sSubString )
if bTest == True:
# Test again if path is valid with this substring
sTempPath = '\\'.join( aNewPath )
if not os.path.exists( sTempPath ): return None
sNewPath = '\\'.join( aNewPath )
print sNewPath
processPath( r'C:\temp\MT_03_03_03\allo.txt', False )
processPath( r'C:\temp\MT_03_04_04\mt_03_04_04_anim_v1.scn', False )
processPath( r'C:\temp\MT_03_05_005_anim\mt_03_05_05_anim_v1.scn', False )
processPath( r'C:\temp\MT_03_06_006\mt_03_06_006_anim_v1.scn', False )
# ============================================================
C:\temp\MT_03_03_003\allo.txt
C:\temp\MT_03_04_004\mt_03_04_004_anim_v1.scn
C:\temp\MT_03_05_005_anim\mt_03_05_005_anim_v1.scn
C:\temp\MT_03_06_006\mt_03_06_006_anim_v1.scn
This is exactly what I was after. Thanks a lot!!
Bernard
On 9/8/05, Kent Johnson <[EMAIL PROTECTED]> wrote:
> Bernard Lebel wrote:
> > Ok I think I understand what is going: I'm using a 0 in the
> > replacement argument, between the two groups. If I try with a letter
> > or other types of characters it works fine. So how can use a digit
> > here?
>
> There is a longer syntax for \1 - \g<1> means the same thing but without the
> ambiguity of where it ends. So you can use r'\g<1>0\2' as your substitution
> string.
>
> >>def matchShot( sSubString ):
> >>
> >> # Create regular expression object
> >> oRe = re.compile( "(\d\d_\d\d\_)(\d\d)" )
> >>
> >> oMatch = oRe.search( sSubString )
> >> if oMatch != None:
> >> sNewString = oRe.sub( r'\10\2', sSubString )
> >> return sNewString
> >> else:
> >> return sSubString
>
> You don't have to do the search, oRe.sub() won't do anything if there is no
> match. Also if you are doing this a lot you should pull the re.compile() out
> of the function (so oRe is a module variable), this is an expensive step that
> only has to be done once.
>
> You hinted in your original post that you are trying to find strings where
> the last _\d\d has only two digits. The re you are using will also match
> something like 'mt_03_04_044_anim' and your matchShot() will change that to
> 'mt_03_04_0044_anim'. If that is not what you want you have to put some kind
> of a guard at the end of the re - something that won't match a digit. If you
> always have the _ at the end it is easy, just use r"(\d\d_\d\d\_)(\d\d_)". If
> you can't count on the underscore you will have to be more clever.
>
> Kent
>
> _______________________________________________
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