Hi Garry,
dau_version = None
while dau_version not in ("2.8", "2.1"):
dau_version = raw_input("\n\tIs the DAU a version 2.1 or 2.8, please
enter only 2.1 or 2.8 ")
print"\n\t\aError! - please enter only 2.1 or 2.8."
else:
print""
I don't know what they else is meant to do, I take it that's when your
while loop exits.
Here's how your code will run -
dau_version = None
(while statement) is dau_version "2.8" or "2.1"? Nope.
dau_version = rawinput("Is...2.8")
print "Error! - please enter only 2.1 or 2.8"
is dau_version "2.8" or "2.1"? Yep - exit loop.
Try doing it like this -
while True:
dau_version = raw_input("\n\tIs the DAU a version 2.1 or 2.8, please\
enter only 2.1 or 2.8 ")
if dau_version in ("2.1", "2.8"):
break
print "Error! - please enter only 2.1 or 2.8"
What will happen is that your while loop will loop forever (as True is
always True).
However, if dau_version is "2.1" or "2.8", the break command will be
called, which exits out of the loop at that point.
So your loop looks like this now -
while True:
get dau_version
if dau_version is right, exit loop here.
print error message
Regards,
Liam Clarke
On 9/25/05, Garry Rowberry <[EMAIL PROTECTED]> wrote:
> I have a call which needs to reply 2.1 or 2.8 and report an error if not:
>
>
> def ask_dau_version():
> """Determine the product issue of the DAU."""
> dau_version = None
> while dau_version not in ("2.8", "2.1"):
> dau_version = raw_input("\n\tIs the DAU a version 2.1 or 2.8, please
> enter only 2.1 or 2.8 ")
> print"\n\t\aError! - please enter only 2.1 or 2.8."
> else:
> print""
> return dau_version
>
> I can see why it isn't working, the error message is in the wrong place, but
> I can't see a simple way around it (wood for the trees)
>
> Gaz
>
> _______________________________________________
> Tutor maillist - Tutor@python.org
> http://mail.python.org/mailman/listinfo/tutor
>
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