Thanks, that helps.
Jorge Godoy wrote:
Johan Geldenhuys <[EMAIL PROTECTED]> writes:
Now that I have the answer (16.800000000000001), How do I round it of to 16.80
? I only need it to be to the closest 1/100.
print "%.2f" % 16.800000000000001
16.80
a = 16.8000000000001
b = "%.2f" % a
b
'16.80'
float(b)
16.800000000000001
str(float(b))
'16.8'
(The reason for the '000000000001' is because of the numeric base used to
represent data -- binary -- and the numeric base I'm requesting the answer to
be in -- decimal.)
Be seeing you,
|
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