-------------------------------- def doLambda(val): print "value 2:", val
commands = [] for value in range(5): print "value 1:", value commands.append(lambda:doLambda(value)) Close but not quite. Try: commands.append(lambda v=value:doLambda(v)) value is a local variable in doLambda so when it executes it uses whatever the global 'value' is set at, which at the end of the loop will be 4. By using the default argument and passing that you freeze the value at whatever it is at the time of setting (a fortuitous by-product of how default parameters work!) HTH, Alan G Author of the learn to program web tutor http://www.freenetpages.co.uk/hp/alan.gauld _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
