| Hi, | | I couldn't get idea how to make the next thing | |||| n=4 #split into so long parts |||| l = (1,2,3,4,5,1,2,3,4,5,1,2,3,4,5) #this is the tuple to split |||| [l[i:i+n] for i in range(0,len(l),n)] | [(1, 2, 3, 4), (5, 1, 2, 3), (4, 5, 1, 2), (3, 4, 5)] | | But I have to make it like this | [(1, 2, 3, 4), (5, 1, 2, 3), (4, 5, 1, 2), (3, 4, 5, default)] | because i use it later in this | |||| result = [l[i:i+n] for i in range(0,len(l),n)] |||| zip(*result) | [(1, 5, 4, 3), (2, 1, 5, 4), (3, 2, 1, 5)] | | and as you can see it, the last element is missing here. |
Since it will always be the last one that is not the correct length; can you just add another line to extend the length of the last one by the correct number of default values (that number being the difference between how many you want and how many you have)? ###### >>> l = (1,2,3,4,5,1,2,3,4,5,1,2,3,4,5) >>> n=4 >>> regrouped = [l[i:i+n] for i in range(0,len(l),n)] >>> default = 'default' >>> regrouped[-1]=list(regrouped[-1]) >>> regrouped[-1].extend([default]*(n-len(regrouped[-1]))) >>> regrouped[-1]=tuple(regrouped[-1]) >>> regrouped [(1, 2, 3, 4), (5, 1, 2, 3), (4, 5, 1, 2), (3, 4, 5, 'default')] >>> >>> ['a']*3 #so you can see what the rhs multiply does ['a', 'a', 'a'] ###### Since tuples cannot be changed, you have to go through the tuple<->list conversion steps. If you can work with a list instead, then these two steps could be eliminated: ###### >>> l = [1,2,3,4,5,1,2,3,4,5,1,2,3,4,5] #using a list instead >>> regrouped = [l[i:i+n] for i in range(0,len(l),n)] >>> regrouped[-1].extend([default]*(n-len(regrouped[-1]))) >>> regrouped [[1, 2, 3, 4], [5, 1, 2, 3], [4, 5, 1, 2], [3, 4, 5, 'default']] >>> ###### /c _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
