Ok. There is an error i made. The links in the HTML-Site are starting
with good.php so there was no way ever to find an link.
re_site = re.compile(r"good\.php.+'")
for a in file:
z = re_site.search(a)
if z != None:
print z.group(0)
This will give me every line starting with "good.php" but does contain
not the first ' at the end, there are more tags and text which ends with
' too. So how can i tell in an regex to stop at the first found ' after
good.php ???
Thank you.
> Hallo.
> I want to parse a website for links of this type:
>
> http://www.example.com/good.php?test=anything&egal=total&nochmal=nummer&so=site&seite=22";>
>
> ---------------------------------------------------------------------
> re_site = re.compile(r'http://\w+.\w+.\w+./good.php?.+";>')
> for a in file:
> z = re_site.search(a)
> if z != None:
> print z.group(0)
>
> ---------------------------------------------------------------------
>
> I still don't understand RE-Expressions. I tried some other expressions
> but didn't get it work.
>
> The End of the link is ">. So it should not be a problem to extract the
> link but it is.
>
> Thank you for the help.
>
> mac
>
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