I would like to know the name of the shortcut (link, I think, in Unix parlance) from which a python program is being invoked. I'd also like to be able to access the directory where the shortcut lives.
Toy example: here's a directory structure: C:\ test\ argtest\ arga.py argb.py testdir\ argc.py arga.py contains: import sys,os print "ARGS:", sys.argv print "WD:", os.getcwd() raw_input() # just to keep the window open argb.py and argc.py are both shortcuts to arga.py When I run arga.py (e.g., by double-clicking on it, I get, as expected: ARGS: ['C:\\test\\argtest\\arga.py'] WD: C:\test\argtest When I run argb.py, I get the same thing. I'd hoped (but didn't really expect) sys.argv would be ['C:\\test\\argtest\\argb.py'] . When I run argc.py, same thing. In this case, I'd hoped sys.argv would be ['C:\\test\\argtest\\testdir\\argc.py']; and os.getcwd() would have given back 'C:\test\argtest\testdir'. Why do I care? Well, I'd like to set up a directory where the shortcut and all its files will live. I'd hoped keying off of the shortcut name might be an easy way to do this. I suspect I'm out of luck: my guess is that windows does all the lookup of what the shortcut points to, and then launches the file pointed to; and by the time Python gets control, the shortcut information is long gone. Anyone know for sure? _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor