On 1/26/06, Alan Gauld <[EMAIL PROTECTED]> wrote: > > I often do a loop over arbitrary number of sequences. I do it like this: > > > >for elem1 in seq1: > > for elem2 in seq2: > > do whatever seq1,seq2 > > this isn`t nice I think. > > Actually its pretty common and not that ugly. > But...
Ok, I see. I was trying to show that I`m (was) unable to pass in an arbitrary number of secuences, but the generator in one of the other posts in thread solves this, right? quite impressive that one I think > > myiterator=geniousfunction(seq1,seq2,seq3) > > > > and then myiterator.next() and have it return the corresponding elemnts > > from all sequences > > The problem is that there are so many different ways you can do that. > Python offers several options but none of them solve all the cases. > > Look at the documentation for > > List Comprehensions > zip() > map() > filter() > reduce() I will. Thanks. > > > seq1 = ['a','b'] > > seq2 = [1,2] > > a 1 > > a 2 > > b 1 > > b 2 > > [a,b for a in seq1 for b in seq2] > > > how do you loop over all the elements that can be returned by > > myiterator? > > return the options as a list of tuples and then use the usual list iteration > techniques. > > for elem in [a,b for a in seq1 for b in seq2]: > # use elem here > that`s nice. Thanks for the replies _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
