On 3/14/06, Steve Nelson <[EMAIL PROTECTED]> wrote: > On 3/14/06, Danny Yoo <[EMAIL PROTECTED]> wrote: > > > The idea is to unpack four single characters as a single 4-byte integer. > > That's really useful, thanks, as I was planning to iterate over each > letter and call ord()
Ok, so experimenting a little further, and looking at the documentation, it seems that len(string) and calcsize (i) must be the same. Is there a reason why 'i' is a 4 byte integer? Doesn't this mean that this method wouldn't scale if I then decided I wanted to use, eg, a 6 byte key instead of a four? Or do I misunderstand? I am also struggling to understand why a 4 byte integer is so large? >>> mystring = "Hello I am Steve" >>> import struct >>> struct.unpack('i', mystring[0:4]) (1819043144,) I can see that the largest number I can generate in a 1 byte integer is 255 - which is (2^8)-1. Is the point that with a 4 byte number I can actually get (2^32)-1 , ie 4294967295? This just seems like a huge number! I suppose I've answered my question... but any comments or clarifications would help a lot. S. _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor