On 3/21/06, stv <[EMAIL PROTECTED]> wrote:
>
> import string
>
> def expand_tree(filetree):
> indent = '\t'
> stack = []
> for f in filetree:
> indents = f.count(indent)
> while len(stack) > indents: stack.pop()
> stack.append(f.strip())
> yield string.join(stack,'')
> if not f.endswith('/'): stack.pop()
> The real-world solution will use a regex to find run
> of spaces at the start of element 'f'.
Hmmm, I'm having to rethink this ... regex will probably not do what I
want (count instance of "indent" ... or, even if regex will do,
there's probably a cleaner solution without it.
Given the subversion problem space (where I can count on 1 space for
each level of child-ness), are there cleaner solutions than this:
indents = len(f) - len(f.lstrip())
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