Hi all,
I was going through the tutorial at http://docs.python.org/tut/node6.html when I
came to the bit about default arguments with this code:
def f(a, L=[]):
L.append(a)
return L
print f(1)
print f(2)
print f(3)
returns:
[1]
[1, 2]
[1, 2, 3]
>From the postings here, I think I understand that this occurs because L is only
initialized when f is first run. However, this code gives some different
results:
def f2(a, L=[]):
if L == []:
L = []
L.append(a)
return L
print f2(1)
print f2(2)
print f2(3)
returns:
[1]
[2]
[3]
I'm not too clear on why this doesn't return the same results as the first. Can
someone enlighten me?
Thanks,
Josh
_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
