> Python regex is a bit more verbose than Perl but you can do the same thing:
>
> In [2]: import re
>
> In [11]: m=re.match("(.{10})(.{10})(.{13})", line)
>
> In [13]: m.group(1, 2, 3)
> Out[13]: ('1234567890', '1234567890', '123456789012 ')That work great. Regex tend to be "expensive" is there a "better" way to do it? _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
