Andrew Robert wrote: > -----BEGIN PGP SIGNED MESSAGE----- > Hash: SHA1 > > When I alter the code to: > > import re,sys > > output = open(r'e:\pycode\new_test.txt','wb') > > for line in open(r'e:\pycode\out_test.txt','rb') : > output.write( re.sub(r'([^\w\s])', lambda s: chr(int(s.group(), 16))) > , line) > > output.close() > > I get the trace: > > Traceback (most recent call last): > File "E:\pycode\sample_decode_file_specials_from_hex.py", line 8, in ? > output.write( re.sub(r'([^\w\s])', lambda s: chr(int(s.group(), > 16))) , line) > TypeError: sub() takes at least 3 arguments (2 given) > > It appears that the code is not recognizing the line. > > I checked the parentheses and they appear to be properly enclosed. > > Any ideas?
You have an argument in the wrong place. Stop trying to do everything in one line! Put the lambda in a def'd function. Put the re.sub on it's own line. You are tripping over unnecessary complexity. I'm not going to fix it any more. Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
