Hi all, I was recently playing with the problem of implementing the floor() functionality, modulo being specifically mentioned in the briefing...
so, after grokking that x = a - (a % b) would do it (i.e. for a = 5.5 and b = 1, you'd get x =5) I felt very pleased... ...until I saw the definiton of modulo. Which would be... def my_mod(x, y): return x - (y*math.floor(x/y)) Ack. My floor() relies on modulo which relies on... floor. So after some Googling, I find a page which indicates that the trick seems to be bit operations - http://www.diycalculator.com/popup-m-round.shtml Problem is; I can't bitshift on floats, so can't test. Can't bitshift on floats in C either. Does anyone know how I could work on a binary representation of a float? Any language at all, I'm desperate... Regards, Liam Clarke _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor