Alan Gauld wrote:
>> This all seems to work okay.
>>
>> I want the assignment operator ('=')
>
> There is no assignment operator in Python, assignment is a
> binding of an object to a name.
>
>> to call the
>> set method transparently on Die instances,
>> as in this fictitious example:
>
> @BCARROLL[Python]|6> mydie = 5
> @BCARROLL[Python]|7> mydie
> <7> 5
>
> But you can fake this by coercing the integer into a new
> Die object. As if you had actually done
>
>
> mydie = Die(mydie.n,5)
>
> And I believe you can do that by implementing the __coerce__
> method. - but I've never tried it...
>
> HTH,
>
> Alan G.
>
If you can do that with __coerce__, I'm not clever enough to figure out
how. IIRC, Python only calls __coerce__ if you're using arithmetic
operators on different types, and only if the operator in question isn't
overloaded to handle this case.
Ex:
In [1]: class coerceTest:
...: def __init__(self, val):
...: self.val=val
...:
...: def __coerce__(self, other):
...: return self.val, other
In [2]: test=coerceTest(5)
In [3]: test
Out[3]: <__main__.coerceTest instance at 0x00E29620>
In [4]: result=test+10
In [5]: result
Out[5]: 15
In [6]: test=5
In [7]: test
Out[7]: 5
(I could've written a test to show that __coerce__ is only called when
no __add__ is defined, but I'm lazy and its time to leave work!)
-Jordan Greenberg
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