On 10/10/06, Dick Moores <[EMAIL PROTECTED]> wrote: > I can get what appears to be a random number precise(?) to 17 digits. > How many base-10 digits would a "53-bit > precision float" have, if converted to base 10? > > >>> 2 ** 52 > 4503599627370496L > >>> 2**53 > 9007199254740992L > >>> > > >>> len(str(2**53))-1 > 15 > > So is the answer to my question something like len(str(2**53)) -1? > (minus 1 because of the L in the long integer)
The string representation of longs doesn't include the 'L': >>> str(9999999999999999999L) '9999999999999999999' >>> repr(9999999999999999999L) '9999999999999999999L' I think the answer is "approximately, yes". But you have to be a bit careful with talking about floating point numbers in terms of decimals. eg: >>> 1.1 1.1000000000000001 -- John. _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
