>> What makes you think so?
>>
>> >>> s = 'l'
>> >>> s += '\n'
>> >>> s
>> 'l\n'
>> >>>
>>
>> Seems to work.... '\n' is just a character like any other.
>
> The issue was to have a newline or return character after every string,
> Here it is just iterpreted as \n alphabet., but not as a return
> character.
Hi Meher,
Are you familiar with Python's rules for escaped character literals?
http://docs.python.org/ref/strings.html
In regular character literals, '\n' is treated as the single newline
character, and not as the literal sequence of a backslash and 'n'. We can
see this concretely:
#############
>>> len('\n')
1
#############
The backslashing notation is necessary in Python because we often need to
talk about characters that are hard to type literally. The escape
characters provide us a coded way to talk about those characters.
If we did want to talk about the string that contains the "backslash" and
"n" sequence, we have to be a little subtle:
##############
>>> len('\\n')
2
##############
Alan and I want to clarify that the way the newlines are being handled in
the original program looks perfectly fine at the moment; I don't think
that's the source of the problem.
_______________________________________________
Tutor maillist - Tutor@python.org
http://mail.python.org/mailman/listinfo/tutor
