Thats ok, I've gotten a ton of other code written, and I'll come back to this tricky part later.
This particular project I've been working on to automate some of my job at work has been an excellent learning experience. :D
On 10/14/06, Chris Hengge <[EMAIL PROTECTED]> wrote:
I was using afile.split("/"), but I'm not sure how to impliment it...
if "/" in afile: (for some reason I can't add 'or "\" in afile' on this line)
outfile = open(afile, 'w') # Open output buffer for writing. (to open the file, I can't split here)
outfile.write(zfile.read(afile)) # Write the file. (zfile.read(afile)) wont work if I split here...)
outfile.close() # Close the output file buffer.On 10/14/06, Kent Johnson <[EMAIL PROTECTED]> wrote:Chris Hengge wrote:
> Ok, last problem with this whole shebang...
>
> When I write the file from the zip, if it is in a subfolder, it will
> error..
> The code below will detect if the file in contained inside a directory
> in the zip, but I just want it to write it like it wasn't.
> Another words
>
> Zipfile.zip looks like this
> file.ext
> file2.ext
> folder/
> anotherfile.ext
>
> file.ext extracts fine, file2.ext extracts file.. but it see's the last
> file as folder/anotherfile.ext and it can't write it.. I tried to figure
> out how to use .split to get it working right.. but I'm not having any
> luck.. Thanks.
>
> for afile in zfile.namelist(): # For every file in the zip.
> # If the file ends with a needed extension, extract it.
> if afile.lower().endswith('.cap') \
> or afile.lower().endswith('.hex') \
> or afile.lower().endswith('.fru') \
> or afile.lower().endswith('.cfg'):
> if afile.__contains__("/"):
This should be spelled
if "/" in afile:
__contains__() is the method used by the python runtime to implement
'in', generally you don't call double-underscore methods yourself.
I think you want
afile = afile.rsplit('/', 1)[-1]
that splits afile on the rightmost '/', if any, and keeps the rightmost
piece. You don't need the test for '/' in afile, the split will work
correctly whether the '/' is present or not.
If you are on Windows you should be prepared for paths containing \ as
well as /. You can use re.split() to split on either one.
Kent
> outfile = open(afile, 'w') # Open output buffer for
> writing.
> outfile.write(zfile.read(afile)) # Write the file.
> outfile.close() # Close the output file buffer.
> else:
> outfile = open(afile, 'w') # Open output buffer for
> writing.
> outfile.write(zfile.read(afile)) # Write the file.
> outfile.close() # Close the output file buffer.
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