Hi Folks,
""" The function takes two arguments, date and number of days. It checks for the right format and if the format is okay, it calculates the end date. """
import string
import datetime
import traceback
def dateCheck(date1,num_days):
flag = True
startdate = None
enddate = None
if num_days < 0 or num_days > 31:
flag = False
print "The argument for -n has to be between 0 and 31"
return (flag,startdate,enddate)
else:
date_lst = string.split(date1,"/")
ln = len(date_lst)
if ln != 3 :
flag = False
print "The argument for -D option has to be in the format: dd/mm/yyyy"
return (flag,startdate,enddate)
else:
date_lst.reverse()
print date_lst
try:
if int(date_lst[0]) < 2000:
flag = False
print "The year cannot be earlier than 2000 and it should be in the format 'yyyy'."
return (flag,startdate,enddate)
except ValueError:
flag = False
err_msg = traceback.format_exc()
index = string.find(err_msg,'Value')
print err_msg[index:]
return (flag,startdate,enddate)
try:
startdate = datetime.date(int(date_lst[0]),int(date_lst[1]),int(date_lst[2]))
enddate = startdate + datetime.timedelta(days=num_days)
print startdate, enddate
except ValueError:
flag = False
startdate = None
enddate = None
err_msg = traceback.format_exc()
index =
string.find(err_msg,'Value')
print err_msg[index:]
return (flag,startdate,enddate)
if enddate > datetime.date.today():
enddate = datetime.date.today()
if startdate > datetime.date.today():
flag = False
startdate = None
enddate = None
print "The -D option should have a date not later than today's date"
return (flag,startdate,enddate)
To HIM you shall return.
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