"Carlos" <[EMAIL PROTECTED]> wrote > Here is the code: > Note: Right now maya is not needed to run the code. > > import time > > #This is the initial state. You can put as many integers as you wish > A_List = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1] > > A_Len = len(A_List) > print 'A_List: ',A_List > print 'A_Len: ', A_Len > B_List = [] > S = A_Len > print S
Not sure why you do this? Why not just use A_Len? > #This is the number of iterations. > for r in range (50): > for i in range (S): > #if i < S-1: > a = A_List[i-1] > b = A_List[i] > c = A_List[i+1] > else: > a = A_List[i-1] > b = A_List[i] > c = A_List[0] > > if a == 1 and b == 1 and c == 1: > X = 0 > elif a == 1 and b == 1 and c == 0: > X = 0 > elif a == 1 and b == 0 and c == 1: > X = 0 I would rewrite these tests to use tuples: if (a,b,c) == (1,1,1): X = 0 elif (a,b,c) == (1,1,0): X = 0 elif (a,b,c) == (1,0,1): X = 0 etc... You could also use a dictionary to make it sligtly more concise: tests = {(1,1,1): 0, (1,1,0): 0,....(1,0,0): 1....} then X = tests[(a,b,c)] I find either option easier to read and maintain than the boolean expressions. > B_List.append(X) > print 'B_List: ',B_List > A_List = B_List > B_List = [] HTH, Alan G. _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor