Dave S wrote:
> On Tuesday 05 December 2006 20:58, Luke Paireepinart wrote:
>
>> Dave S wrote:
>>
>>> Hi all,
>>>
>>> Struggling with python & XP again. My app needs to know if a certain
>>> program is running on my XP box
>>>
>>> Ideal world - I can get the output of 'tasklist.exe' into a string.
>>>
>>> I have tried
>>>
>>> os.execl('....')
>>> It throws the output to the terminal + I need the exact path to the
>>> executable (a bit of a trial)
>>>
>>> and
>>> os.startfile('...')
>>> it throws the output to a different window, but no exact path needed
>>>
>>> Any ideas how I can catch the output ?
>>>
>> You could try redirecting sys.stdout to a file-like class instance you
>> create.
>>
>>
>
> OK ... could you give me a bit more on that ? ... probably me being a bit
> dense :)
>
Um...
#test.py
class FileLikeObject(object):
def __init__(self,current_stdout):
self.data = []
self.oldstdout = current_stdout
def write(self,arg):
if arg != '\n':
self.data.append(arg)
def output(self):
sys.stdout = self.oldstdout
print self.data
sys.stdout = self
import sys
f = FileLikeObject(sys.stdout)
sys.stdout = f
print "hello."
f.output()
print "hi"
f.output()
#-----------
Be careful playing with the dark magic....
Don't forget that print goes to stdout.
HTH,
-Luke
> Cheers
>
> Dave
>
>
>
>
>
>>> Cheers
>>>
>>> Dave
>>>
>>>
>>> _______________________________________________
>>> Tutor maillist - Tutor@python.org
>>> http://mail.python.org/mailman/listinfo/tutor
>>>
>
>
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