"Jason Coggins" <[EMAIL PROTECTED]> wrote
> I have the following function in a program:
>
> os.popen('filename.py')
So what happened?
Did you get an error message? If so what?
> What I want to do is launch the program in the os.popen() function.
Do you want to lasunch it or interact with it.
If its only launch then os.system might be easier.
> The file I am trying to launch is located in the same directory
> as the program the function is contained in.
That may not be the same directory you start the program from.
Its always safer to use (or build) the full path.
--
Alan Gauld
Author of the Learn to Program web site
http://www.freenetpages.co.uk/hp/alan.gauld
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