elis aeris schreef: > > > I am capturing a screen shot, but then the image was already > > > image, how do I .load it ? > > it's not image.load()
I see. In that case, you can't use the method I described; that only works if you load the image from disk (as far as I know). I think you'd better use getdata() as Alan described. Something like this, if you need to access the pixels column-by-column (Is that really what you want? You still haven't told us): # ... image = ImageGrab.grab ((rect.left, rect.top, rect.right, rect.bottom)) pixels = image.getdata() for x in xrange(0, 1024): for y in xrange(0, 768): print pixels[x + y * 768] Note: pixel indices start from 0, not from 1. If you want to access them row-by-row (as is generally more often the case) and you don't have a special need to have the x and y available: image = ImageGrab.grab ((rect.left, rect.top, rect.right, rect.bottom)) for pixel in image.getdata(): print pixel Anyway, you're printing a lot of pixels (786432 actually)... is that really what you want? -- If I have been able to see further, it was only because I stood on the shoulders of giants. -- Isaac Newton Roel Schroeven _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor