John: One way to handle the situation of longitude is to make everything
west of the Greenwich meridan a negative value until -180 degrees and
everything east of Greenwich a positive value. HTH.
Albert
John <[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED]
07/10/2007 04:22 PM
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[Tutor] An interesting case... of east vs. west
I was trying to read in a tab delimited file i was given with lat and lon,
the thing is I needed decimal lat, and decimal long... well, anyway I
think you can see what my problem was:
for i in range(0,344)
y=d[i][2].split('\xb0')
x=d[i][3].split('\xb0')
ydeg,ymin=y[0].strip(),y[1].rstrip('\' N').rstrip("\' S")
xdeg,xmin=x[0].strip(),x[1].rstrip("\' E").rstrip("\' W")
if re.search('\ZW','x[1]') xmin=-1*xmin
if re.search('\ZS','y[1]') ymin=-1*ymin
declat=int(ydeg)+(float(ymin)/60)
declon=int(xdeg)+(float(xmin)/60)
The thing is, it isn't terribly robust (I'm not even positive it's working
correctly!!). For instance, as you might have guessed I was given Lat and
Lon in the following format:
STNA 45° 49' N 08° 38' E
STNB 46° 58' 19° 33' E
STNC 53°33' -9°54'
STND 51°32' N 12°54' W
Some indicating north or some, and some not. This wasn't a concern, as I
knew they were all North. However, the West / East issue is another story.
Anyone have a more elegant solution?
-john
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_______________________________________________
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