At 10:16 AM 8/6/2007, Eric Brunson wrote:
Your point about efficiency is well-taken.
>def makechange( amount, denominations ):
>
> coins = {}
> for d in denominations:
> coins[d] = int( amount/d )
> amount = amount%d
>
> return coins
OK, I used this this way:
============================
def makechange( amount, denominations ):
coins = {}
for d in denominations:
coins[d] = int( amount/d )
amount = amount%d
return coins
denominations = (2000, 1000, 500, 100, 50, 25, 10, 5, 1)
amount = 2218
print makechange(2218, denominations)
==================================
And get:
{1: 3, 100: 2, 5: 1, 1000: 0, 10: 1, 2000: 1, 50: 0, 500: 0, 25: 0}
That's the correct change: 3 pennies, 2 $1 bills, 1 nickel, no $10
bills, 1 dime, 1 $20 bill, no half-dollars, no $5 bills, no quarters.
For amount = 3288:
{1: 3, 100: 2, 5: 0, 1000: 1, 10: 1, 2000: 1, 50: 1, 500: 0, 25: 1}
Why those weird orders?
Dick
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