Hi Boyks, Boykie Mackay wrote: > Hi guys, > > I have come across a bit of code to find if a group of numbers is odd or > even.The code snippet is shown below: > > if not n&1: > return false > > The above should return false for all even numbers,numbers being > represented by n.I have tried to wrap my head around the 'not n&1' but > I'm failing to understand what's going on.Could someone please explain
the single '&' is a bitwise and operator. every odd number has the first bit set so <odd number>&1 returns 1. The binray representation of : 1 0001 2 0010 3 0011 4 0100 >>> 1&1 1 >>> 2&1 0 >>> 3&1 1 >>> 4&1 0 HTH Ewald _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
