Ricardo Aráoz wrote: > Kent Johnson wrote: >> or use slice assignment: >> tmpSegs[:] = [ seg.split(self.ElemSep) for seg in tmpSegs ] > > Won't the slice assignment create a new list and then assign it to the > old list (which the OP is trying to avoid)?
Yes, it will, thanks! You can assign a generator expression to the list: tmpSegs[:] = ( seg.split(self.ElemSep) for seg in tmpSegs ) I don't know if that creates a temp list or assigns directly into the old list though. At the byte-code level at least it seems to assign the iterator to the slice. Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
