> s=set()
> [s.add(tuple(x)) for x in myEntries]
> myEntries = [list(x) for x in list(s)]
This could be written more concisely as...
s = set(tuple(x) for x in myEntries)
myEntries = [list(x) for x in list(s)]
Generator expressions are really cool.
Not what the OP asked for exactly. He wanted to eliminate duplicates by
adding their last columns. He said the last column is a number of hours that
pertain to the first four columns. When you apply your method, it will not
get rid of duplicate projects, just circumstances where the number of hours
is equivalent also, and of course, not add the hours like they should be. I
like the dictionary approach for this personally...
di = {}
for x in myEntries:
try: di[x[:3]]+=x[4]
except KeyError: di[x[:3]] = x[4]
This can be written even smaller and cleaner if you use the default value
method...
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