So super(A, c) refers to the baseclass object?
I don't like this. It partially suggests that A is a superclass of B.
I guess I have to be sure to notice the second parameter which tells of
which instance I'm finding the superclass.
fyi I totally didn't notice the first parameter of super... was it there in
previous versions of python?
----- Original Message -----
From: "Andreas Kostyrka" <[EMAIL PROTECTED]>
To: "tiger12506" <[EMAIL PROTECTED]>
Cc: <tutor@python.org>
Sent: Friday, March 21, 2008 4:25 AM
Subject: Re: [Tutor] Calling super classs __init__?
class A(object):
v=lambda self: "A"
class B(object):
v=lambda self: "B"
class C(B,A):
v=lambda self: "C"
print C.__mro__
c=C()
print c.v()
print super(C, c).v()
print super(B, c).v()
(<class '__main__.C'>, <class '__main__.B'>, <class '__main__.A'>, <type
'object'>)
C
B
A
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