Kepala Pening wrote: > import re > > items = [] > for line in open('data.txt'): > items.append(re.sub('\n', '', line).split(' '))
Hmm. So much to say about so little code! - the re.sub() is not needed - the split() will remove the trailing newline: In [53]: 'a b\n'.split() Out[53]: ['a', 'b'] - you don't need re to replace a fixed character, you can use str.replace(): In [55]: 'a b\n'.replace('\n', '') Out[55]: 'a b' - If you just want to strip the trailing newline you can use strip() or rstrip(), with or without args, depending on how strict you want to be: In [56]: 'a b\n'.strip() Out[56]: 'a b' - It's not clear that the OP wants a list of lines, but if so, a list comprehension is much more succinct: items = [ line.split() for line in open('data.txt') ] would do the job just fine. Kent _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor