At 01:29 PM 4/17/2008, Hansen, Mike wrote:
>
>
> > -----Original Message-----
> > From: [EMAIL PROTECTED]
> > [mailto:[EMAIL PROTECTED] On Behalf Of Dick Moores
> > Sent: Thursday, April 17, 2008 2:21 PM
> > To: Python Tutor List
> > Subject: Re: [Tutor] datetime module problem
> >
> > At 06:29 AM 4/17/2008, Kent Johnson wrote:
> > >Dick Moores wrote:
> > >
> > >>>You could either create n with hours=minutes=0, or round the
> > >>>difference up to the next whole number of days.
> > >>I have no idea how to implement either of your suggestions as to
> > >>how to eliminate it. Could you please spell them both out?
> > >
> > >1.
> > >
> > >In [17]: n=datetime.today()
> > >In [18]: n=datetime(n.year, n.month, n.day)
> > >In [19]: n
> > >Out[19]: datetime.datetime(2008, 4, 17, 0, 0)
> > >
> > >2.
> > >
> > >In [20]: diff=y-n
> > >In [21]: diff
> > >Out[21]: datetime.timedelta(0, 57464, 721369)
> > >In [22]: days = diff.days
> > >In [23]: if diff.seconds or diff.microseconds:
> > >    ....:     days += 1
> > >    ....:
> > >    ....:
> > >In [24]: days
> > >Out[24]: 1
> >
> > Thanks, Kent. So here's where I am now:
> > <http://py77.python.pastebin.com/f5da44111>
> >
> > The script calculates correctly, but note the output, lines 34, 39,
> > 49, 53. Please show me how to print these in the form 4/17/2007. I've
> > tried everything I could think of.
> >
> > Dick
> >
>
>
>In [23]: import datetime
>
>In [24]: x = datetime.datetime.now()
>
>In [25]: x
>Out[25]: datetime.datetime(2008, 4, 17, 14, 24, 18, 447000)
>
>In [26]: x.month
>Out[26]: 4
>
>In [27]: x.day
>Out[27]: 17
>
>In [28]: x.year
>Out[28]: 2008
>
>In [30]: print "%s/%s/%s" %(x.month, x.day, x.year, )
>4/17/2008
>
>Does that help? There's probably another way to do it, but this seems to
>work.

Yes, I'd finally done that (honest), so that will take care of lines 
39, 49, but not 34, 53 of <http://py77.python.pastebin.com/f5da44111>.

Thanks,

Dick



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