eeck. Not that I advocate parsing files by line, but if you need to do it:
lines = list(file)[16:]
or
lines_iter = iter(file)
zip(lines_iter, xrange(16))
for line in lines_iter:
Andreas
Am Montag, den 21.04.2008, 14:42 +0000 schrieb linuxian iandsd:
> Another horrid solution
>
> #!/usr/bin/python
> # line number does not change so we use that
> # the data we're looking for does not have a (unique) close
> tag (htmllib ????)
>
> import re, urllib2
> file=urllib2.urlopen('http://10.1.2.201/server-status')
> n=0
> for line in file:
> n=n+1
> if n==16:
> print re.sub('requests.*','',line)[4:].strip()
> elif n==17:
> print re.sub('requests.*','',line)[4:].strip()
>
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