Jordan Greenberg wrote:
> def addcommas(s): # assumes type(s)==str
> b=[]
> l=len(s)
> for i,v in enumerate(s):
> i+=1 # easier to understand w/ 1-based indexing, i think.
> b.append(v)
>
> if (l-i)%3==0 and not i==l:
> b.append(',')
> return ''.join(b)
>
>
> or, somewhat more tersely:
>
>
> def addcommas2(s):
> l=len(s)
> return ''.join(v+',' if (l-(i+1))%3==0 and not i+1-l==0
> else v for i,v in enumerate(s))
Excellent, thanks Jordan! That's much more elegant, and efficient, than
my juggling act :)
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