On Sun, 2008-06-29 at 10:20 +0200, [EMAIL PROTECTED] wrote: > Message: 1 > Date: Sat, 28 Jun 2008 21:53:44 -0400 > From: Kirk Z Bailey <[EMAIL PROTECTED]> > Subject: [Tutor] arrays in python > To: tutor@python.org > Message-ID: <[EMAIL PROTECTED]> > Content-Type: text/plain; charset=ISO-8859-1; format=flowed > > Just wondering, if I can find a way to do a 2 dimensional array in > python. 1 dimension would be a list it would seem; for 2, I could use > a > list of lists? > > Strange how I can't think of ever needing one since I discovered > snake > charming, but so many languages do foo dimensional arrays, it would > seem > like there ought to be a way to do it in python. > > --
>>> from numpy import * # import the necessary module >>> arry = array((1,2,3,4)) # create a rank-one array >>> print arry [1 2 3 4] >>> print arry.shape (4,) # this means it is a rank 1 array with a length of 4 (the trailing comma means it is a tuple) To get to the first element in the array: >>> print arry[0] 1 To get to the last element: >>> print arry[-1] 4 >>> arry2 = array(([5,6,7,8],[9,10,11,12])) # create a a rank-two array, two-dimensional, if wish >>> print arry2 [[ 5 6 7 8] [ 9 10 11 12]] >>> print arry2.shape # > (2, 4) # this means that it is a rank 2 (ie 2-dimensional) array, with each axis having a length of 4 >>> To get to the first element in the first axis: >>> print arry2[0,0] 5 To get to the last element in the second axis: >>>> print arry2[1,-1] 12 You can slice it, reshape it, literally you can contort in way you want! Does this help? Kinuthia... _______________________________________________ Tutor maillist - Tutor@python.org http://mail.python.org/mailman/listinfo/tutor
